SOLVE (i) (ii) and (iv)
Attachments:
Answers
Answered by
0
if x=2
k*(2)2-5*2+6=0
4k-10+6=0
4k-4=0
4k=4
k=4/4
k=1
it is 1 St solution
k*(2)2-5*2+6=0
4k-10+6=0
4k-4=0
4k=4
k=4/4
k=1
it is 1 St solution
minakshisamvedp5o49l:
what about the other two solutions
Answered by
0
these are 1 and 2 answers
Attachments:
Similar questions
English,
7 months ago
Math,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
History,
1 year ago
Science,
1 year ago