Solve ...............
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Q 1 =>
perimeter = 64
formula we know as side^2
=> side = square root of 64 = 8
perimeter = side × 4
=> 8 × 4 = 32
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( I AM DOING ONLY 1 FROM EACH. SO REST ALL U TRY. THEY ARE ALSO IN THE SAME PROCESS.)
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Q2 =>
AREA of the metal plate = 32 × 12m^2
area of small squares = 4 × 4
=> total numbers of squares = 32 × 12 / 4 × 4 = 24
hence 24 squares can be done.
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Q3 =>
AREA OF RECTANGLE = 24 × 17
= 408m^2
AREA OF SQUARE = 21 × 21m^2
==== 441m^2
DIFFERENCE = 441m^2 - 408m^2 = 33m^2
HENCE SQUARE 'S AREA IS GREATER THAN RECTANGLE BY 33m^2
perimeter = 64
formula we know as side^2
=> side = square root of 64 = 8
perimeter = side × 4
=> 8 × 4 = 32
------------------------------------------------------------
( I AM DOING ONLY 1 FROM EACH. SO REST ALL U TRY. THEY ARE ALSO IN THE SAME PROCESS.)
-----------------------------------------------------------
Q2 =>
AREA of the metal plate = 32 × 12m^2
area of small squares = 4 × 4
=> total numbers of squares = 32 × 12 / 4 × 4 = 24
hence 24 squares can be done.
--------------------'--'-----------------------------------
Q3 =>
AREA OF RECTANGLE = 24 × 17
= 408m^2
AREA OF SQUARE = 21 × 21m^2
==== 441m^2
DIFFERENCE = 441m^2 - 408m^2 = 33m^2
HENCE SQUARE 'S AREA IS GREATER THAN RECTANGLE BY 33m^2
nancy1973:
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