Question

Solve
i)
$(x + 3)(x + 3)$
ii)
$(2y + 5)(2y + 5)$
​

Answer 1

Step-by-step explanation:

(x+a)(x+b)=x^2+(a+b)x+ab

(i)(x+3)(x+3)=x^2+(3+3)x+3(3)

=x^2+6x+9

(ii)(2y+5)(2y+5)=(2y)^2+(5+5)(2y)+5(5)

=4y^2+20y+25

Answer 2

• Answer -

→ (x + 3)²

→ (x)² + (3)² + 2 × x × 3

→ x² + 9 + 6x

→ (2y + 5)²

→ (2y)² + (5)² + 2 × 2y × 5

→ 4y² + 25 + 20y

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