Question

solve I will mark as brainliest​

Answer 1

Answer:

The Answer is (d)

Step-by-step explanation:

.....

Answer 2

Answer:

Let:

=> $\tt{\sqrt{1 + \sqrt{1 + \sqrt{1 + \sqrt{1 + ...}}}} = x}$

Squaring on both sides:

=> $\tt{1 + \sqrt{1 + \sqrt{1 + \sqrt{1 + \sqrt{1 + ...}}}} = x^{2}}$

We know that $\tt{\sqrt{1 + \sqrt{1 + \sqrt{1 + \sqrt{1 + ...}}}} = x}$

Thus:

=> $\tt{1 + x = x^{2}}$

Solve this quadratic equation. You get the roots as:

=> $\tt{\frac{ 1 \pm \sqrt{5}}{2}}$

$\tt{Put \: \sqrt{5} \: as \: 2.2:}$

=> $\tt{\frac{ 1 \pm \sqrt{5}}{2}}$ = $\tt{\frac{ 1 \pm 2.2}{2}}$

=> -0.6 Or 1.6

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