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2.7) I) Find the sum of money on which the interest equals ₹6770 in 1 year at the interest rate of 5% per annum .
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P = SI × 100 / R × T
= 6770 × 100 / 5 × 1
= 6770 × 20
= 135400
II) In how many years will ₹1200 amount to ₹1488 at the interest rate of 3% per annum?
Ans ↓
SI = A - P
= 1488 - 1200
= 288
T = SI × 100 / P × R
= 288 × 100 / 1200 × 3
= 288 / 12 × 3
= 288 / 36
= 8
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