Math, asked by mafujasheikh407, 5 months ago

solve i) x^2+3x-18=0​

Answers

Answered by priyadharshini3725
0

Answer:

The answer is below

Step-by-step explanation:

x²+3x-18 = x²-3x+6x-18

=x(x-3)6(x-3) = 0

=(x-3)(x+6)

x-3=0 ; x+6=0

x= +3 ; x = -6

Ans: x= 3,-6

Answered by Anonymous
3

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x² + 3x - 18 = 0

x² + 6x - 3x - 18 = 0

x (x + 6) - 3 (x + 6) = 0

(x - 3) = 0 or (x + 6) = 0

x = 3 or x = - 6

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