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if a 1200 W electric iron is used daily for 30 minutes ,how much total electricity is consumed in the month of may?
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Answered by
0
Answer:
Given that,
Power =1200W=1.2kWh
Time = 30 min / day × 30 days =0.5h×30= 15 h
Energy =Power×Time=1.2×15= 18kWh.
Answered by
0
Answer:
Power =1200W=1.2kWh
Time = 30 min / day × 30 days =0.5h×30= 15 h
Energy =Power×Time=1.2×15= 18kWh
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