Solve if a+b+c=10,ab+BC+ca=5 find a²+b²+c²
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Answered by
3
Squaring on both sides
(A+b+c) ²=10²
A²+b²+c²+2(ab+bc+ca) =100
A²+b²+c²+10=100
A²+b²+c²=100-10=90
I hope this will help you
By DEVANSH
(A+b+c) ²=10²
A²+b²+c²+2(ab+bc+ca) =100
A²+b²+c²+10=100
A²+b²+c²=100-10=90
I hope this will help you
By DEVANSH
Answered by
2
a + b + c = 10
Square on both sides,
(a + b + c)² = 10²
a² + b² + c² + 2(ab + bc + ca) =100
a² +b² + c² + 10 = 100
a² + b² + c² = 100-10=90
I hope this will help you
-by ABHAY
Square on both sides,
(a + b + c)² = 10²
a² + b² + c² + 2(ab + bc + ca) =100
a² +b² + c² + 10 = 100
a² + b² + c² = 100-10=90
I hope this will help you
-by ABHAY
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