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f(ρ) = aρ + b ... (1)
f(γ) = aγ + b ... (2)
Subtracting (2) from (1) gives:
f(ρ) - f(γ) = a ( ρ - γ ) => a = ( f(ρ) - f(γ) ) / ( ρ - γ )
Subtracting γ times (1) from ρ times (2) gives:
ρf(γ) - γf(ρ) = b ( ρ - γ ) => b = ( ρf(γ) - γf(ρ) ) / ( ρ - γ )
Thus
f(x) = ax + b
= ( ( f(ρ) - f(γ) ) x + ρf(γ) - γf(ρ) ) / ( ρ - γ )
= ( ( f(ρ) ( x - γ ) - f(γ) ( x - ρ ) ) / ( ρ - γ )
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f(x)=ax+b
f(§)=a§+b
f(p)=ap+b
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