Question

Solve if you can!
:)​

Answer 1

Answer:

(i) is $\frac{\sqrt{3}}{2}$, and (ii) is $\frac{\sqrt{3}}{2}$.

Step-by-step explanation:

We have that $\sin 3A = 1$, then taking the inverse of sine of both sides gives

$3A = \arcsin 1 = 90^{\circ}$,

hence,

$A = 30^{\circ}$

Then (i) is simply $\sin 2A = \sin 60^\circ = \frac{\sqrt{3}}{2}$

and (ii) is $\cos A = \cos 30^{\circ} = \frac{\sqrt{3}}{2}$