Math, asked by vishuvarku, 1 year ago

solve illustration 2

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Answered by arpit281
1
factors  of  a3 + b3 = ( a + b ) ( a2 +ab + b2 ), hence

2 ( sin2A + cos2 A) ( sin4 A + cos4 A + sin2A cos2A) - 3 ( sin4A + cos4A ) 
 + 1
=  2* 1 * ( sin4A + cos4A + sin2A cos2A ) - 3 ( sin4A + cos4 A ) + 1

=  2 sin2A cos2A -  sin4A - cos4 A  +  1

=  - ( sin2A  + cos2A 2 + 1 = 0 =  RHS
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