solve immediately please please
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in ΔABC and ΔADE
∠B=∠D (corresponding angles)
∠C=∠E ("")
ΔABC≈ΔADE
AD/AB=AE/AC=DE/BC (corresponding parts of similar Δs)
⇒AD/AB=DE/BC AND AE/AC=DE/BC
⇒2.4/AB=2/5 AND 3.2/AC=2/5
⇒12=2AB AND 16=2AC
⇒AB=6 cm AND AC=8 cm
NOW, AC=AE+EC
⇒ AC-AE=CE
⇒8-3.2=CE
⇒4.8 cm = CE
ALSO, BD=AB-AD
⇒BD=6-2.4= 3.6 cm
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