Question

Solve in a half reaction method with step by step

Pb3o4+8hcl--->3pbcl2+cl2+4h2o

If you don't know then leave it plz.

Answer 1

Pb38/3O4 + 8 HCl-I → 3 PbIICl2-I + Cl20 + 4 H2O

This is an oxidation-reduction (redox) reaction:

3 Pb8/3 + 2 e- → 3 PbII (reduction)

2 Cl-I - 2 e- → 2 Cl0 (oxidation)

Change the oxidation states