Question

solve in completing square method
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chapter name - quadratic equations
class 10th ​

Answer 1

Answer:

$3 {x}^{2} + 14x + 8 = 0 \\ 9 {x}^{2} + 42x + 24 = 0 \\ {(3x)}^{2} + 2 \times 3x \times 7 + {7}^{2} - {7}^{2} + 24 = 0 \\ {(3x - 7)}^{2} = 49 - 24 \\ {(3x - 7)}^{2} = 25 \\ 3x - 7 = 5 \: \: \: \: \: \: \: \: \: \: 3x - 7 = - 5 \\ x = 4 \: \: \: \: \: \: \: x = \frac{2}{3}$