Question

solve in factor theorem
p(x)=4x^3 - 12x^2+14x-3
g(x)= x-1​

Answer 1

Answer:

• solve in factor theorem
• p(x)=4x^3 - 12x^2+14x-3
• g(x)= x-1

Step-by-step explanation:

According to remainder theorem, We know if f(x) is divided by ( x - a) , then remainder = f(a) ,

If f(x) is divided by (x-a) we have taken it (x -a) = 0 .So, Remainder would be f(a) .

Now, p(x) = 4x³ -12x²+14x - 3 .

If p(x) is divided by 2x-1 , then (2x-1) = 0 , x = 1/2 .So when p(x) is divided by (2x-1) , it leaves a remainder p(1/2)

p(1/2)

= 4(1/2)³ -12(1/2)²+14(1/2)-3

= 4(⅛)-12(1/4)+7-3

= 1/2 -3 + 7 - 3

= 1/2 +1

= 3/2

\therefore∴ The remainder when 4x³-12x²+14x-3 divided by 2x-1 is 3/2

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