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Answers
Answer:
till Q4 can't click all so other questions I'll just write.
Q5)solution:- Given, polynomial 3x³- 4x²- 7x-5
when x=3, then
p(3)= 3×3³-4×3²-7×3-5
= 3×27-4×9-21-5
= 81-36-21-5
= 81-62
= 19
When, x= -3 then,
p(-3)= 3×(-3)³-4×(-3)²-7×(-3)-5
= 3×(-27)-4×9+21-5
= -81-36+21-5
= -122+21
= -101
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Q6) solution:- Given, p(y) = y/2-5
To find: p(2) and p(2/5)
when, y=2
p(2)= 2/2-5
= 2-10
2
= -8
2
= -4
When, y= 2
5
p(2/5) = 2/5 -5
2
= 2 × 1 -5
5 2
= 1/5 - 5
= 1-25/5
= -24/5
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Q7 solution:- Given, p(t)= t³+2t³+t
When, t=3
p(3) = 3³+2×3²+3
= 27+2×9+3
= 27+18+3
= 48
When, t= (-3)
p(-3)=(-3)³+2×(-3)²+(-3)
= -27+2×9-3
= -27+18-3
= -30+18
= -12
When, t= 4
p(4)= 4³+2×4²+4
= 64+2×16+4
= 64+32+4
= 100
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Hope it will help you
