Solve in quadratic equation form
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Area of rectangle=105cm²
Length=x
Breadth=105/x. (1)
Perimeter=44cm
1
Breadth=½×44-x. (2)
Equate both
So,105/x=½×44-x
105=½×44-x×x
105=22-x²
-x²=105+22 =127
-x=√127=11.26
Hence,breadth of rectangle is 11.26cm.
Length=x
Breadth=105/x. (1)
Perimeter=44cm
1
Breadth=½×44-x. (2)
Equate both
So,105/x=½×44-x
105=½×44-x×x
105=22-x²
-x²=105+22 =127
-x=√127=11.26
Hence,breadth of rectangle is 11.26cm.
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