Math, asked by Anonymous, 1 year ago

solve in substitution method root2x+root3y=0,root3x+root8y=0

Answers

Answered by anvi555
12


root2x+ root3y=0 -(1)
root3x+root8y=0 -(2)
by substitution,
x= 0- root3y/2
x= -root3y/2
put this value of x in (2)
root3(-root3y/2)+root8y=0
-3y/root2+root8y=0
-3y+root16y/root2=0
-3y+root16y=0*root2
-3y+4y=0
y=0
x=-root3(0)/2
x=0/2
x=0
#plz mark this answer as the brainliest answer ^_^

Anonymous: ok anvi what u like that u do
anvi555: sry that was my old one means from mumma's side my original name is ANVI S. SINGH
Anonymous: subhojit Das
anvi555: nyc name u have ^_^
Anonymous: my Papa side is subhojit Das and my mamas is subhojit mohanty
Anonymous: but all are telling me by love banty
Anonymous: u also what a nice name
anvi555: thanks
Anonymous: hello beautiful girl
anvi555: hii
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