Question

solve ineqality -8x ≤ 5x - 3 <7

Answer 1

Happy to help mate^_^^_^

Answer 2

We will need to solve the inequation one by one.

First case :

$- 8x \leqslant 5x - 3 \\ \\ = - 8x - 5x \leqslant - 3 \\ \\ = - 13x \leqslant - 3 \\ \\ = 13x \geqslant 3 \\ \\ = x \geqslant \frac{3}{13}$

Second case :

$5x - 3 < 7 \\ \\ = 5x < 7 + 3 \\ \\ = 5x < 10 \\ \\ = x < \frac{10}{5} \\ \\ = x < 2$

Therefore the solved inequation,

$\frac{3}{13} \geqslant x < 2$