solve int_sec^2x dx /(1 + tan x )( 2+ tan x )
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Explanation:
This is a u-subsitution problem. Our goal is to cancel out the numerator. Let u=1+tanx. Then du=sec2xdx and dx=dusec2x
=∫sec2xu⋅dusec2x
=∫(1u)du
This can be integrated as ∫(1x)dx=ln|x|+C.
=ln|u|+C
=ln|1+tanx|+C, where C is a constant
Hopefully this helps!
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