Question

solve integral of dx/2x^2-1

Answer 1

dx/2(x^2-1/2)............
this expression is of the form ζdx/(x²-a²) =1/2a log((x-a)/(x+a)).....
so if u hold a²=1/2 and solve accordingly u will get the answer....

Answer 2

d x\2x^2-1=x\2x 
=1\2 answer