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Integration for Sin^2x dx
mehtadimple1234:
cos2x/2
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Q ..sin^2 x dx
= 1 - cos2 x / 2
= 1/2(1 - cos2 x) dx
= 1/2 ( 1 ) dx - 1/2 (cos2 x ) dx
= x / 2 - (sin 2 x /2) 1 / 2 + c
=> x / 2 - sin 2x / 4 + c
HOPE HELPED
#@®¥@n#
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HERE IS UR ANSWER
Q ..sin^2 x dx
= 1 - cos2 x / 2
= 1/2(1 - cos2 x) dx
= 1/2 ( 1 ) dx - 1/2 (cos2 x ) dx
= x / 2 - (sin 2 x /2) 1 / 2 + c
=> x / 2 - sin 2x / 4 + c
HOPE HELPED
#@®¥@n#
;-)
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