Question

solve is substitution, elimination and cross multiplication method: 2x+y=35, 3x+4y=65

Answer 1

Answer:

x= 15 , y= 5

Step-by-step explanation:

2x+y=35   ....(1)

3x+4y=65  ....(2)

2×Eqn(2)−3×Eqn(1) we get

6x+8y−6x−3y=130−105

⇒5y=25 or y=  

5

25

​  

=5

Substitute y=5 in (1) we get

2x+5=35⇒2x=35−5=30

or x=  

2

30

​  

=15

∴x=15,y=5

Answer 2

Answer:

ok

Step-by-step explanation:

substitution method

since:- 2x +y = 35

then y= 35 - 2x

so, 2x + 4(35-2x) = 65

2x + 140 - 8x = 65

2x - 8x = 65 - 140

-6x = -75

6x = 75

x = 12.5

y = 35 - 2×12.5

35 - 25

= 10

x= 12.5

y= 10