Question

Solve it ...!

1 - Find the least square number which is divisible by 2, 3,4,5,6.

2- a number when divided by 32, the remainder is 28 . the same number when divided by 8 , what will be the remainder?​

Answer 1

Answer:

$\Large{\underline{\underline{\bf{Question 1}}}}$

$\fbox{Solution}$

$\red{ The Least number divisible by 2, 3 , 4, 5, 6 is clearly their LCM Which is 60.}$

$\green{\bold{\underline{\underline{Since , }}}}$

$\fbox{60 = 2 × 2 × 3 × 5.}$

$\red{ To Make it a perfect square it multiply by 3 × 5 .}$

So,The Required number is

$\fbox{2×2×3×3×5×5 = 900}$

$\Large{\underline{\bf{Question 2}}}}$

$\fbox{Solution}$

$\Large\red{GIVEN,}$

Let the number x be , When didvide by 3

The remainder is 28 and Quotient is y.

⁂ x ⟹ 32 × y + 28

⟹ 8 ( 4y + 3 ) + 4

So, the required remainder will be

$\fbox{⟹ 4}$

$<marquee> Peaku05</marquee>$

Answer 2

1. $\huge{ \underline{ \underline{ \green{ \sf{ SoLuTiOn :-}}}}}$

LCM of 3,4,5, and 6 = 60

60 = 2 × 2 × 3 × 5

Here, 3 and 5 are not in pair .

so multiply it by the stated numbers.

=> 60 × 3 × 5 = 900

Therefore,

${\purple{\boxed{\mid{\bold{900 \: is \: the \: least \: perfect \: square \: divisible \: by \: 3 ,\: 4, \: 5 \: and \: 6}}}}}$

2. $\huge{ \underline{ \underline{ \green{ \sf{ SoLuTiOn:-}}}}}$

If a number gives a remainder of 28 on dividing it by 32 .

So it can be written in the form of

32k + 28

=32k + 24 + 4

= 8 × 4 × k + 8 × 3 + 4

= 8(4k + 3 )+4

So,

${\red{\boxed{\large{\bold{The \: remainder \: is \: 4}}}}}$

Hope its helpful ❤