Question

Solve it
(1-x²)(1-y)dx=xy(1+y)dy​

Answer 1

Answer:

Step-by-step explanation:

1−x  

2

)(1−y)dx=xy(1+y)dy

x

1−x  

2

 

​

dx=  

1−y

y  

2

+y

​

dy

Integrating both sides, we get

logx−  

2

x  

2

 

​

=−∫(y+2+  

y−1

2

​

)dy

⇒logx−  

2

x  

2

 

​

=−  

2

y  

2

 

​

−2y+2log(y−1)

log(x)(1−y)  

2

=c−  

2

1

​

y  

2

−2y+  

2

1

​

x  

2