Math, asked by Anonymous, 1 year ago

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Answers

Answered by anuj00799
5
the smallest amount of one dollar and two dollars bills the cashier may give it to the man

1 × 1 + 10 × 2 = 21 .

he must give the menu multiple of 21 that is
21 or 42 or 63 or 84 or 105 or 126 or 147 or 168 or 187

without exceeding 200. out of all these
number of only 105 can be added to multiple of 5
to sum up to make 200 altogether


so he must give the balance of 95 in five dollar bills.


therefore the cashier must give 5 one dollars bills
50 two dollar bills and 19 five dollar bills



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