Question

solve it ............​

Answer 1

Answer:

⚡⚡⚡ Hola ⚡⚡⚡

⏩Here's ur answer :

Given :

Operating central frequency = 10 GHz = 10^10 Hz

Available for communication channel = 1% of 10^10 Hz

= (1/100) × 10^10 = 10^8 Hz

bandwidth of each telephone channel = 5 KHz = 5000 Hz = 5 × 10^3 Hz

Then,

n × (bandwidth of each telephone channel) = 10^8

=> n × 5 × 10^3 = 10^8

=> n = 10^8/5×10^3 = 10×10^4/5

=> n = 2 × 10^4

Therefore,

No. of telephone channels = 2 × 10^4

...........................⚡Hakuna Matata⚡

Answer 2

Answer:

Operating central frequency = 10 GHz = 10^10 Hz

Available for communication channel = 1% of 10^10 Hz

= (1/100) x 10^10 = 10^8 Hz

bandwidth of each telephone channel = 5 KHz = 5000 Hz = 5 x 10^3 Hz

Then,

nx (bandwidth of each telephone channel) = 10^8

=> n × 5 × 10^3 = 10^8

=> n = 10^8/5x10^3 = 10x10^4/5

=> n = 2 x 10^4