Question

Solve it .....................​

Answer 1

$\huge\underline\purple{\sf ♡ Answer:}$

$\large{\boxed{\sf\theta = 30° }}$

$\huge\underline\purple{\sf ♡ Solution:}$

Given :-

Wavelength $\sf{\lambda = 6000 Angstrom}$

Convert it into m :-

$\large{\sf \lambda=6×{10}^{-7}m}$

Width (a) = $\sf{24×{10}^{-5}×{10}^{-2}m}$

To find :-

Angular position $\sf{\theta}$=?

━━━━━━━━━━━━━━━━━━━━━━━━━━

We know that ,

$\large{♡}$$\large{\boxed{\sf a\:sin\theta=2\lambda}}$

ON PUTTING VALUE :-

$\large\implies{\sf sin\:\theta={\frac{2\lambda}{a}}}$

$\large\implies{\sf {\frac{2×6×{10}^{-7}}{24×{10}^{-7}}}}$

$\large\implies{\sf {\frac{1}{2}}}$

Here we got sin $\sf{\theta={\frac{1}{2}}}$

We know that sin 30° =1/2

Therefore ,

Angular position of second minimum from central maximum is 30°

$\huge\red{♡}$$\huge\red{\boxed{\sf \theta=30°}}$