Question

solve it??????????????? ​

Answer 1

Step-by-step explanation:

Given: ABCD is a rhombus

To prove: AB2 + BC2 + CD2 + AD2 = AC2 + BD2

Proof:

We know, diagonals of a rhombus bisect at right angles.

Therefore, from triangle AOB,

AB2 = AO2 + OB2

=(1/2AC)² +(1/2BD)²

=1/4AC +1/4BD

4AB2 = AC2 + BD2

Thus, AB2 + BC2 + CD2 + DA2 = 4AB2 = AC2 + BD2

[As AB = BC = CD = DA]

hope this will help you