Question

solve it.....,...................... ​

Answer 1

Answer:

2x^2+3y^2=35. (I)

x^2/2+y^2/3=5

=3x^2+2y^2/6=5

=3x^2+2y^2=30. (ii)

from equation (I)

=2x^2=35-3y^2

=x^2=35-3y^2/2. (iii)

putting the value of x^2 in equation (ii)

3(35-3y^2)/2+2y^2=30

=(105-9y^2)/2+2y^2=30

=(105-9y^2+4y^2)/2=30

=105-5y^2=60

=-5y^2=60-105

=-5y^2=-45

=5y^2=45

=y^2=9. (iv)

putting the value of y^2 from equation (iv) into equation (iii)

x^2=(35-9)/2

=x^2=(26)/2

=x^2=13

therefore y=3

x=√13

Answer 2

Answers:-

Refer to the attachments.