Math, asked by peace4dilshad, 7 months ago

solve it ..................​

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Answered by Anonymous
58

Question :

Solve the following simultaneous equations:

 \dfrac{27}{x  - 2}  +  \dfrac{31}{y + 3}  = 85

 \dfrac{31}{x - 2}  +  \dfrac{27}{y + 3}  = 89

Solution :

Let X=\dfrac{1}{x-2}

Y =\dfrac{1}{y+3}

27X+31Y=85...(1)

31X+27Y=89....(2)

___________________

Now by substitution method

27X+31Y=85

⇒X = \dfrac{85-31Y}{27}...(3)

put the value of X in equation (2)

31(\dfrac{85-31Y}{27})+27Y=89

\dfrac{2635-961Y+729Y}{27}=89

2635-232Y=2403

⇒Y = 1

put the value of Y in equation (3)

Then ,

X = \dfrac{85-31}{27}

= \dfrac{54}{27}

=2

Now

2=\dfrac{1}{x-2}

\dfrac{1}{2}=x-2

⇒x=5/2

1=\dfrac{1}{y+3}

⇒y+3=1

⇒y=-2

Value of x =5/2 and y =-2

Answered by prathampatel204
1

Step-by-step explanation:

Follow the above attachment given

See the methpd must be diffrent frm ur classes or scul

As they add and subtract to find m and n

But here i have multiplied to get the answer ⏩ fast

Mark it as a brainlist anwer

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