Question

solve it....................​

Answer 1

Answer:

Step-by-step explanation:

Answer is in the image attached. Hope this will help you.!!!

Answer 2

Answer:

$\boxed{I= \frac{x^3}{3}+x^2-7x+ 12(ln|x+2|)}$

Step-by-step explanation:

Let $I=\int \frac{x^3+4x^2-3x-2}{x+2}dx$

Now adding and subtracting 12 in numerator;

$I=\int \frac{(x^3+4x^2-3x-14)+12}{x+2}dx\\\\=>I=\int\frac{x^3+4x^2-3x-14}{x+2}dx+\int\frac{12}{x+2}dx\\\\=>I=\int\frac{(x+2)(x^2+2x-7)}{(x+2)}dx+14(ln|x+2|)\\\\=>I=\int (x^2+2x-7)dx+12(ln|x+2|)\\\\\\=>\boxed{I= \frac{x^3}{3}+x^2-7x+ 12(ln|x+2|)}$

Hope this answer helped you :)