Solve it.........................
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Answered by
80
Given :
{cos(90 - ∅) sec(90 - ∅) tan ∅} / {cosec(90 - ∅) sin(90 - ∅) cot(90 - ∅) + {tan(90 - ∅)} / cot∅
=> {sin × cosec × tan} / {sec × cos × tan} + {cot/cot}
=> {sin × (1/sin) × tan / sec × 1/sec × tan} + 1 [ Since, cot / cot = 1 ]
=> tan/tan + 1
=> 1 + 1 = 2 R.H.S
Hence, Proved
Answered by
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