Question

Solve it.........................




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Answer 1

$\huge\red{Answer}$

Given :

{cos(90 - ∅) sec(90 - ∅) tan ∅} / {cosec(90 - ∅) sin(90 - ∅) cot(90 - ∅) + {tan(90 - ∅)} / cot∅

=> {sin × cosec × tan} / {sec × cos × tan} + {cot/cot}

=> {sin × (1/sin) × tan / sec × 1/sec × tan} + 1 [ Since, cot / cot = 1 ]

=> tan/tan + 1

=> 1 + 1 = 2 R.H.S

Hence, Proved

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Answer 2

UR QUESTION:-

$\sf\implies \frac{cos(90\degree - \theta)sec(90\degree- \theta )tan \theta}{cosec \theta(90 \degree- \theta)sin(90 \degree- \theta)cot(90 \degree - \theta)} +\frac{tan(90\degree - \theta)}{cot \theta}=2$

UR ANSWER ✓

$\sf\implies \frac{cos(90\degree - \theta)sec(90\degree- \theta )tan \theta}{cosec \theta (90 \degree- \theta)sin(90 \degree- \theta)cot(90\degree - \theta)} +\frac{tan(90\degree - \theta)}{cot \theta}=2$

$\sf\implies \frac{sin \times cosec \times tan}{sec\times cos \times tan}+[\frac{cot}{cot}]$

$\sf\implies [sin \times \frac{1}{sin} \times \frac{tan}{sec} \times \frac{1}{sec} \times tan] +1[since \frac{cot}{cot} =1]$

$\sf\implies \frac{tan}{tan}+1$

$\sf\implies 1 + 1 = 2 R.H.S$

$\huge\purple{\text{hence proved,}}$