Question

solve it...................​

Answer 1

Answer:

The problem can be rewritten as

sigma infinity n = 0 is equal to the $1/3^{n}$

so ,

And we can see that is a Geometric series. To understand wheather the series converges or not we have to solve the following inequality :-

 1/3 is smaller than 1

So we can finally state that the series converges to the following value :-

1 / 1-q  , where q = 1/3

so ,

     =  1 / 1 - 1/3

    = 1 / 2/3

    = 3/2

Step-by-step explanation:

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Answer 2

Answer:

sagnik4444

14 minutes ago

Math

Secondary School

+5 pts

Answered

Solve it...................​

1

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sharwankumarjakhar

sharwankumarjakharVirtuoso

Answer:

Step-by-step explanation:

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Answers

shiva00756

BrainlyMehu

sharwankumarjakhar

ad9620767

skchoudary

SkchoudaryAce

Answer:

The problem can be rewritten as

sigma infinity n = 0 is equal to the 1/3^{n}

so ,

And we can see that is a Geometric series. To understand wheather the series converges or not we have to solve the following inequality :-

1/3 is smaller than 1

So we can finally state that the series converges to the following value :-

1 / 1-q , where q = 1/3

so ,

= 1 / 1 - 1/3

= 1 / 2/3

= 3/2

Step-by-step explanation:

Please mark me as brainliest. Please