Chemistry, asked by Anonymous, 10 months ago

Solve it!!!!!!!!!✌️✌️✌️​

Attachments:

Answers

Answered by Anonymous
1

Here is your answer in the attachment hope it help ✌️

Attachments:
Answered by InfiniteSoul
8

\sf{\huge{\mathfrak{\pink{\underline{Question}}}}}

  • Calculate the volume of dry air at STP that occupies 28 cm^3 at 14°C and 750 mmHg pressure when saturated with water vapour. The vapour pressure of water at 14°C is 12 mmHg.

\sf{\huge{\mathfrak{\pink{\underline{Solution}}}}}

\sf{\bold{\green{\underline{\underline{Given}}}}}

  • volume of dry air + water= 28cm^3
  • Temperature = 14°C
  • pressure of dry air + water = 750mmHg
  • vapour pressure of water at 14°C= 12mmHg

\sf{\bold{\blue{\underline{\underline{To\:Find}}}}}

  • volume of dry air at STP = ???

\sf{\bold{\purple{\underline{\underline{ explanation }}}}}

pressure due to dry air = total pressure - vapour pressure

pressure due to dry air =( 750 - 12 )mmHG

pressure due to dry air = 738 mmHg

  • convert temp. into Kelvin

temperature = 14°C + 273 = 287 K

  • using gas equation

\sf{\bold{\red{\boxed{\dfrac{PV}{T}  = \dfrac{P_1V_1}{T}}}}}

\sf{\dfrac{738\times 28}{287} = \dfrac{750\times v_1}{273}}

\sf{V_1 = \dfrac{738 \times 28 \times 273}{287 \times 760}}

\sf{V_1 = \dfrac{5641272}{218120}}

\sf{v_1 = 25.9 cm^3}

\sf{\bold{\red{\boxed{\dag 25.9cm^3}}}}

_________________❤

Similar questions