Math, asked by mohi8957, 9 months ago

Solve it ... √3+1/√3-1 = a-b √3

Answers

Answered by DrNykterstein
0

</p><p> =  =  &gt;  \:  \:  \frac{ \sqrt{3}  + 1}{ \sqrt{3}  - 1}  = a - b \sqrt{3} \\  \\  =  =  &gt;  \:  \:  \frac{ \sqrt{3} + 1 }{ \sqrt{3}  - 1}  \times  \frac{ \sqrt{3}  + 1}{ \sqrt{3}  + 1}   = a - b \sqrt{3}  \\  \\  =  =  &gt;  \:  \:  \frac{ {( \sqrt{3}  + 1)}^{2} }{ {( \sqrt{3} )}^{2}  -  {(1)}^{2} }  = a - b \sqrt{3}  \\  \\  =  =  &gt;  \:  \:  \frac{3 + 1 + 2 \sqrt{3} }{3 - 1}  = a - b \sqrt{3} \\  \\  =  =  &gt;  \:  \:  \frac{ \cancel{2}(2 +  \sqrt{3}) }{ \cancel{2}}   = a - b \sqrt{3}  \\  \\  =  =  &gt;  \:  \: 2 +  \sqrt{3}  = a - b \sqrt{3}  \\  \\  =  =  &gt;  \:  \: 2 - ( - 1 \sqrt{3} ) = a - b \sqrt{3} </p><p></p><p>

On comparing,

a = 2 and b = -1

Answered by bhuvijindal
0

Answer:

hope it would be help full

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