Question

solve it:(3°-2°)×6°​

Answer 1

$( {3}^{0} - {2}^{0} ) \times {6}^{0} \\ = > (1 - 1) \times 1 \\ = > 0 \times 1 = 0$

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Answer 2

Answer:

Its zero,

because for example 5^0=1

(something power zero is equal to 1.)

=(3^0-2^0)×6^0

=(1-1)×1

=1-1×1

(By using BODMAS rule)

=1-1

=0

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