solve it...................
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Answered by
5
Hey!
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10^2y = 25
10^-y = ?
( 10^y) ^2 = 5^2
10^y = 5
( 10^y)^-1 = 5^-1
[ We can also write 5^-1 as 1/5 ]
10^-y = 1/5
Thus, 10^-y = 1/5
__________________
Hope it helps...!!!
__________________
10^2y = 25
10^-y = ?
( 10^y) ^2 = 5^2
10^y = 5
( 10^y)^-1 = 5^-1
[ We can also write 5^-1 as 1/5 ]
10^-y = 1/5
Thus, 10^-y = 1/5
__________________
Hope it helps...!!!
HimanshuRaj012:
hey
Answered by
4
PLEASE TYPE THE QUESTION.
Final Answer : 1/5
Steps:
1)

We know that 10^y is always positive.
Therefore, 10^y is 5 and we rejected 10^y = -5.
Now,

So, Our final answer is 1/5 .
Final Answer : 1/5
Steps:
1)
We know that 10^y is always positive.
Therefore, 10^y is 5 and we rejected 10^y = -5.
Now,
So, Our final answer is 1/5 .
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