Question

Solve it ..................................

Answer 1

We are given one piece of info:

$\frac{x}{y} + \frac{y}{x} = -1 \\ \\ \\ \implies \frac{x^2+y^2}{xy}=-1 \\ \\ \\ \implies x^2+y^2=-xy \\ \\ \\ \implies x^2+xy+y^2=0$

Now, we  can find the required value as follows:

$x^3-y^3 \\ \\ \\ = (x-y)(x^2+xy+y^2) \\ \\ \\ = (x-y) \times 0 \\ \\ \\ = 0 \\ \\ \\ \implies \boxed{x^3-y^3=0}$

Thus, the final answer is 0.


Hope it helps
Purva
Brainly Community

Answer 2

Given Expression :

$\frac{x}{y} + \frac{y}{x} = - 1$

To Find :

The value of x³-y³

Solution :

Refer to the above attachment !!

The required value of x³-y³ = 0 .

#Be Brainly !!