Solve it ...............
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Refer to attachment,
dx is a small length,
So it's dimensions will be [L]
And,
[a] = [L]
Since dimensions of LHS ≠ dimensions of RHS
Therefore,
Following integral is wrong.
!
dx is a small length,
So it's dimensions will be [L]
And,
[a] = [L]
Since dimensions of LHS ≠ dimensions of RHS
Therefore,
Following integral is wrong.
!
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alishakhan3:
nai smjh aaya ;-(
where ?
Shuru s
ok let me explain it
ok
but, I got it
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