Solve it...........................
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angle BCA = 1/2 angle AOB ( angles subtended from the same arc at the centre is twice that of the one subtended at the circumference)
angle BCA = 20 degrees.
angle BAC = 1/2 angle BOC (Same as above )
angle BAC = 15 degrees.
therefore angle ABC = (180-(20+15))
= 145 degrees...
angle BCA = 20 degrees.
angle BAC = 1/2 angle BOC (Same as above )
angle BAC = 15 degrees.
therefore angle ABC = (180-(20+15))
= 145 degrees...
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