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Given,
AB || DE .
To find angle ACD,
Construction: Draw a line pushing through point C such that the line is parallel to both AB and DE.
Solution:AngleBAC=AngleACX(alternate angles)....................(1)
Angle CDE=Angle DCX(alternate angles)..................(2)
Adding equations 1 and 2,
35°+53°=88°
=>Angle DCA=88°
hope it helps......
plz mark it Brainliest if it helps.......!!!!
AB || DE .
To find angle ACD,
Construction: Draw a line pushing through point C such that the line is parallel to both AB and DE.
Solution:AngleBAC=AngleACX(alternate angles)....................(1)
Angle CDE=Angle DCX(alternate angles)..................(2)
Adding equations 1 and 2,
35°+53°=88°
=>Angle DCA=88°
hope it helps......
plz mark it Brainliest if it helps.......!!!!
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