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Here is the proof.
Let 3log4 = y ... (1)
Taking logarithm on both the sides,
log 3log4 = log y
log 4 × log 3 = log y [log am = m log a]
log 3 × log 4 = log y
log 4log 3 = log y [m log a = log am]
Taking anti-logarithm on both the sides,
antilog (log 4log 3) = antilog (log y)
4log 3 = y ... (2)
From (1) and (2), 3log4 = 4log 3
Hence, the result is proved.
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samridh01:
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