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( ax - 3/2 b)^2 -1/4 b^2= 0
( ax - 3/2b) = +- 1/2 b
ax = +- 1/2 b + 3/2b
x = 2b/a , b/a
✌✌✌Dhruv✌✌✌✌
( ax - 3/2b) = +- 1/2 b
ax = +- 1/2 b + 3/2b
x = 2b/a , b/a
✌✌✌Dhruv✌✌✌✌
Answered by
2
Hey !
a²x² - 3abx + 2b² = 0
a²x² - 3abx = - 2b²
divide each term with a² both sides of the
equation ,
x² - 3bx/a = - 2b²/a²
x² - 2 × x × (3b/2a)+(3b/2a)² = ( 3b/2a )² - 2b²/a²
( x - 3b/2a )² = 9b²/4a² - 2b² /a²
= ( 9b² - 4b² ) /a²
= 5b²/a²
x - 3b/2a = ± √ ( 5b²/a² )
x = 3b/2a ± √5 ( b/a )
= [ 3b ± 2√5 b ] / 2a
= ( 3 ± 2√5 )b/ 2a
= (3+2√5)b/2a , (3-2√5)b/2a
a²x² - 3abx + 2b² = 0
a²x² - 3abx = - 2b²
divide each term with a² both sides of the
equation ,
x² - 3bx/a = - 2b²/a²
x² - 2 × x × (3b/2a)+(3b/2a)² = ( 3b/2a )² - 2b²/a²
( x - 3b/2a )² = 9b²/4a² - 2b² /a²
= ( 9b² - 4b² ) /a²
= 5b²/a²
x - 3b/2a = ± √ ( 5b²/a² )
x = 3b/2a ± √5 ( b/a )
= [ 3b ± 2√5 b ] / 2a
= ( 3 ± 2√5 )b/ 2a
= (3+2√5)b/2a , (3-2√5)b/2a
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