Question

solve it..............​

Answer 1

By Distance formula

√[(at²-a/t²)² + (2at+2a/t)²]

  = √[a²(t²-1/t²)² + 4a²(t+1/t)²]

  = √[a²(t⁴+1/t⁴-2) + 4a²(t²+1/t²+2)]

  = a √(t⁴+1/t⁴-2+4t²+4/t²+8)

  = a √ (t⁴+4t²+6+4/t²+1/t⁴)

  = a √ (t + 1/t)⁴

  = a √ [(t + 1/t)²]²

  = a (t + 1/t)²

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