Solve it
A=60°,B=30°,tan(A - B)=tanA - tanB /1+ tanA tanB
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Hey there! Thanks for the question!
Given,
A = 60° , B = 30°
To verify : tan(A - B) = tanA-tanB / 1 + tanA tanB.
Now,
tan( 60 - 30 ) = tan60 - tan30 / 1 + tan60° tan30°
We know that, tan30 = 1/√3 , tan60 = √3
tan30° = ( √3) - ( 1/√3) / 1 + ( √3) ( 1/√3)
1/√3 = ( 3 - 1 / √3 ) / 2
1/√3 = 2/√3 / ( 2 )
1/√3 = 1/√3
Both sides of the equation are equal!
Therefore, We proved and verified tan (A-B) = tanA-tanB / 1+ tan A tan B , for A = 60° , B = 30°
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