English, asked by bznznzbb257, 22 days ago

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Answered by Sriya4281
2

Q 3) 3 sin 23°/cos 67° +4 sec47°/cosec 43°

=3×cos(90°-23°)/cos 67° +4(cosec 90°-47°)/cosec 43°

=3cos 67°/cos 67° + 4 cosec 43°/cosec 43°

=3×1 + 4×1

=3+4=7

see the upper attachment (1 and 2 solution)

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