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Q 3) 3 sin 23°/cos 67° +4 sec47°/cosec 43°
=3×cos(90°-23°)/cos 67° +4(cosec 90°-47°)/cosec 43°
=3cos 67°/cos 67° + 4 cosec 43°/cosec 43°
=3×1 + 4×1
=3+4=7
see the upper attachment (1 and 2 solution)
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