solve it.....and describe it .....
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Voltage on AB = 12V
Eq Resistance in CD = (6*6)/(6+6) = 3ohm
R(AC) = R(CD)
So , V(AC) = V(CD) = 12/2 = 6V
Now , I*6 = 6
So , I = 1A
Eq Resistance in CD = (6*6)/(6+6) = 3ohm
R(AC) = R(CD)
So , V(AC) = V(CD) = 12/2 = 6V
Now , I*6 = 6
So , I = 1A
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