Solve it and explain
Attachments:
Answers
Answered by
1
Hey !!!
3u³ - 4u² - 12u + 16
3u³ - 12u - 4u² + 16 [Rearranging term ]
3u ( u² - 4 ) - 4(u² - 4)
(3u - 4) ( u² - 4)
(3u -4)(u² - 4 )
(3u - 4) ( u² - 2²)
(3u - 4 )(u + 2 ) (u - 2)
•°• a² - b² = (a + b) ( a - b )
APPLYING this rule
hence , we got its factor .
(3u - 4 ) ( u + 2 ) ( u - 2 )
hence factorised here ✔
__________________________
Hope it helps you !!!
@Rajukumar111
3u³ - 4u² - 12u + 16
3u³ - 12u - 4u² + 16 [Rearranging term ]
3u ( u² - 4 ) - 4(u² - 4)
(3u - 4) ( u² - 4)
(3u -4)(u² - 4 )
(3u - 4) ( u² - 2²)
(3u - 4 )(u + 2 ) (u - 2)
•°• a² - b² = (a + b) ( a - b )
APPLYING this rule
hence , we got its factor .
(3u - 4 ) ( u + 2 ) ( u - 2 )
hence factorised here ✔
__________________________
Hope it helps you !!!
@Rajukumar111
Answered by
0
i think you understand
Attachments:
Similar questions