Question

solve it and follow ​

Answer 1

Step-by-step explanation:

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Answer 2

$= > a + \frac{1}{a} = \frac{17}{4}$

$= > \frac{{a}^{2} + 1 }{a} = \frac{17}{4}$

$= > 4 {a}^{2} + 4 = 17a$

$= > 4 {a}^{2} - 17a + 4 = 0$